Impossible math equations...

[Coyotemen]

All right, let's see if this goes over well at all. Just list any math problem that you know the answer to and see if the person below you knows it.

There is a hole with a circumference and depth both totalling 15 feet (each). How much dirt is in the hole?

[Bad Infinitum]

No dirt, it's a hole.

Solve for "x":
x?x

EDIT: the question mark is a "not equal to" sign...the forums couldn't even solve the problem.

[Coyotemen]

That is correct...you wouldn't believe how many people actually tried to work that out in my college algebra class lol.

[Sinn Féin's Ireland]

What about the cubed root of -3.4

[Anime Daisuki]

Is that a point or a times?

[Mindless Radio Puppets]

sinn said:

What about the cubed root of -3.4

-1.5036...(and on it runs)

Ad Infinitum...no clue...0 maybe?

[Twobagger]

How about...

x/x = 0

[Mindless Radio Puppets]

x = 0?

[Twobagger]

ah, but that would leave you with 0/0, and we can't have that.

[Mindless Radio Puppets]

*blinks* Why not?

[Twobagger]

That would make 0 divided by 0. We in math can't divide by zero.

[Mindless Radio Puppets]

We could pretend the normal rules don't apply....

[Twobagger]

Ok!
Looks like you win then.

[Mindless Radio Puppets]

Yay! (You can tell I'm lost when I start making up my own rules...)

[Bad Infinitum]

Here's one for the logic nerds...

Jean is shorter than Brutus, but taller than Imhotep. Imhotep is taller than Jean, but shorter than Lord Scotland. Lord Scotland is twice the height of Jean and Brutus combined, but only a tenth of the height of Millsy. Millsy is at a constant height of [x-y]. If Jean stands exactly one nautical mile away from Lord Scotland, how tall is Imhotep?

We'll reveal the answers to the problem at the end of the program.

[Twobagger]

Impossible to solve as the first two sentences contradict each other. (=

[Bad Infinitum]

Incorrect answer.

Anywho, the title of the thread isn't "very very hard but still somehow solvable math equations."

[Twobagger]

prestobrendochango said:

Here's one for the logic nerds...

Jean is [...] taller than Imhotep. Imhotep is taller than Jean [...]

Eh, seems correct enough from my point of view... I probably just can't see what you've shown me.
Go on, do tell the answer... it's filled with enough obtuse measurements that I just have to hear the answer and the logic behind it.

Edited for clarity.

[Three Prongs]

is it "not"

[Echolilia]

Jan 11, 2007 14:40:29 GMT -5 Mindless Radio Puppets said:

sinn said:

What about the cubed root of -3.4

-1.5036...(and on it runs)

And what are the other two cube roots?

[La Vida De Sangre]

[Aersoldorf]

if a=1 and b=1 then a=b
this means that a^2 = ab
then a^2 - b^2 = ab - b^2
then (a+b)(a-b)=b(a-b)
then a+b=b
then 1+1=1
then 2=1

[Boltor]

Since a=1 and b=1, (a-b)=0 so line 5 is unachievable, since you cannot divide both sides by 0 to remove (a-b)...............

[Aersoldorf]

very nice boltor, i use that to make sure my children's math teachers are acceptable

[Aersoldorf]

4 boys go hiking and get caught out after dark. They come to a river that they must cross to get home. there is a log across the river, but only 2 of them may cross together at any 1 time. the river is too wide to throw their only flashlight across, so it must be hand carried back across for the others to use (must use flashlight to cross river). when 2 boys travel together, they travel at the speed of the slower boy. each boy can cross at a different speed. If one boy can cross in 1 minute, one takes 2 minutes, the third takes 5 minutes and the slowest takes 10 minutes, then what is the least amount of time necessary for all four boys to cross the river?

[La Vida De Sangre]

Jun 8, 2011 8:53:08 GMT -5 Aersoldorf said:

if a=1 and b=1 then a=b
this means that a^2 = ab
then a^2 - b^2 = ab - b^2
then (a+b)(a-b)=b(a-b)
then a+b=b
then 1+1=1
then 2=1

High five for troll science!

[Boltor]

Ugh

[Aersoldorf]

You're supposed to answer, not grunt

[Anartonia]

Jun 8, 2011 12:04:33 GMT -5 Aersoldorf said:

4 boys go hiking and get caught out after dark. They come to a river that they must cross to get home. there is a log across the river, but only 2 of them may cross together at any 1 time. the river is too wide to throw their only flashlight across, so it must be hand carried back across for the others to use (must use flashlight to cross river). when 2 boys travel together, they travel at the speed of the slower boy. each boy can cross at a different speed. If one boy can cross in 1 minute, one takes 2 minutes, the third takes 5 minutes and the slowest takes 10 minutes, then what is the least amount of time necessary for all four boys to cross the river?

I think 20 minutes, but I'm not sure.

[Aersoldorf]

no, not 20 minutes